ICPC 2017
ICPC 2017

F. Posterize

event sponsor ICPC 2017 Problem F Posterize Time limit: 2 seconds Pixels in a digital picture can be represented with three integers in the range 0 to 255 that indicate the intensity of the red, green, and blue colors. To compress an image or to create an a...

Updated May 21, 2026
Track ICPC
Year 2017
Statement Text + PDF
TeXC++Statement textStatement PDF

Problem Statement

Formatted from the contest statement text, with sample tests broken out into copyable blocks.

Time limit 2 seconds

Pixels in a digital picture can be represented with three integers in the range 0 to 255 that indicate the intensity of the red, green, and blue colors. To compress an image or to create an artistic effect, many photo-editing tools include a “posterize” operation which works as follows. Each color channel is examined separately; this problem focuses only on the red channel. Rather than allow all integers from 0 to 255 for the red channel, a posterized image allows at most k integers from this range. Each pixel’s original red intensity is replaced with the nearest of the allowed integers. The photo-editing tool selects a set of k integers that minimizes the sum of the squared errors introduced across all pixels in the original image. If there are n pixels that have original red values r1 , . . . , rn , and k allowed integers v1 , . . . , vk , the sum of squared errors is defined as

      min (ri − vj )2 .
      1≤j≤k
i=1

Your task is to compute the minimum achievable sum of squared errors, given parameter k and a description of the red intensities of an image’s pixels.

Input

The first line of the input contains two integers d (1 ≤ d ≤ 256), the number of distinct red values that occur in the original image, and k (1 ≤ k ≤ d), the number of distinct red values allowed in the posterized image. The remaining d lines indicate the number of pixels of the image having various red values. Each such line contains two integers r (0 ≤ r ≤ 255) and p (1 ≤ p ≤ 226 ), where r is a red intensity value and p is the number of pixels having red intensity r. Those d lines are given in increasing order of red value.

Output

Display the sum of the squared errors for an optimally chosen set of k allowed integer values.

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Sample Tests

Sample 1
Sample Input
2 1
50 20000
150 10000
Sample Output
66670000
Sample 2
Sample Input
2 2
50 20000
150 10000
Sample Output
0
Sample 3
Sample Input
4 2
0 30000
25 30000
50 30000
255 30000
Sample Output
37500000

Editorial

The solution write-up is rendered from the LaTeX source, with equations kept live through MathJax.

Key Observations

  • Write the structural observations that make the problem tractable.

  • State any useful invariant, monotonicity property, graph interpretation, or combinatorial reformulation.

  • If the constraints matter, explain exactly which part of the solution they enable.

Algorithm

  1. Describe the data structures and the state maintained by the algorithm.

  2. Explain the processing order and why it is sufficient.

  3. Mention corner cases explicitly if they affect the implementation.

Correctness Proof

We prove that the algorithm returns the correct answer.

Lemma 1.

State the first key claim.

Proof.

Provide a concise proof.

Lemma 2.

State the next claim if needed.

Proof.

Provide a concise proof.

Theorem.

The algorithm outputs the correct answer for every valid input.

Proof.

Combine the lemmas and finish the argument.

Complexity Analysis

State the running time and memory usage in terms of the input size.

Implementation Notes

  • Mention any non-obvious implementation detail that is easy to get wrong.

  • Mention numeric limits, indexing conventions, or tie-breaking rules if relevant.

Code

C++ solution used for this page.

C++

Clean code view with a raw-file link when you want the original source.

Raw file
#include <bits/stdc++.h>
using namespace std;

namespace {

void solve() {
    // Fill in the full solution logic for the problem here.
}

}  // namespace

int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);

    solve();
    return 0;
}

Source Files and Assets

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