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A Bold Proposition

Let A be an affine plane over a radically integral local field F with residual characteristic p. We consider an open oriented line section U of A with normalized Haar measure m. Define f(m, p) as t...

Source sync Apr 19, 2026
Problem #0836
Level Level 06
Solved By 5,435
Languages C++, Python
Answer \texttt{aprilfoolsjoke
Length 341 words
analytic_mathconstructivealgebra

Problem Statement

This archive keeps the full statement, math, and original media on the page.

Let \(A\) be an affine plane over a radically integral local field \(F\) with residual characteristic \(p\).

We consider an open oriented line section \(U\) of \(A\) with normalized Haar measure \(m\).

Define \(f(m, p)\) as the maximal possible discriminant of the jacobian associated to the orthogonal kernel embedding of \(U\) into \(A\).

Find \(f(20230401, 57)\). Give as your answer the concatenation of the first letters of each bolded word.

Problem 836: A Bold Proposition

Mathematical Foundation

Theorem (Non-existence of Coherent Interpretation). The compound expression “radically integral local field” does not correspond to any standard mathematical object. The problem statement is intentionally constructed from plausible-sounding but mutually incompatible mathematical terminology.

Proof. A “local field” is a well-defined concept (a non-discrete, locally compact, totally disconnected topological field, e.g., Qp\mathbb{Q}_p or Fq((t))\mathbb{F}_q((t))). However, the modifier “radically integral” is not a recognized qualifier for local fields in any standard reference (Serre, Neukirch, Cassels-Froehlich). Similarly, while “Jacobian” and “orthogonal kernel embedding” are individually meaningful in appropriate contexts (algebraic geometry and functional analysis, respectively), their composition in this sentence does not form a coherent mathematical construction. The parameter m=20230401m = 20230401 encodes the date April 1, 2023, confirming the problem is an April Fools’ Day puzzle. \square

Lemma (Extraction Rule). The answer is obtained by concatenating the first letter of each bolded word in the problem statement.

Proof. The problem explicitly instructs: “Give as your answer the concatenation of the first letters of each bolded word.” The bolded words, in order, are:

PhraseBolded wordsFirst letters
affine planeaffine, planea, p
radically integral local fieldradically, integral, local, fieldr, i, l, f
open oriented line sectionopen, oriented, line, sectiono, o, l, s
jacobianjacobianj
orthogonal kernel embeddingorthogonal, kernel, embeddingo, k, e

Concatenation: aprilfoolsjoke=aprilfoolsjokea \cdot p \cdot r \cdot i \cdot l \cdot f \cdot o \cdot o \cdot l \cdot s \cdot j \cdot o \cdot k \cdot e = \texttt{aprilfoolsjoke}. \square

Editorial

We enumerate the admissible parameter range, discard candidates that violate the derived bounds or arithmetic constraints, and update the final set or total whenever a candidate passes the acceptance test.

Pseudocode

    bold_words = ["affine", "plane", "radically", "integral", "local",
                  "field", "open", "oriented", "line", "section",
                  "jacobian", "orthogonal", "kernel", "embedding"]
    Return concatenate(w[0] for w in bold_words)

Complexity Analysis

  • Time: O(1)O(1).
  • Space: O(1)O(1).

Answer

aprilfoolsjoke\boxed{\texttt{aprilfoolsjoke}}

Code

Each problem page includes the exact C++ and Python source files from the local archive.

C++ project_euler/problem_836/solution.cpp
#include <bits/stdc++.h>
using namespace std;

int main() {
    // Problem 836: A Bold Proposition (April Fools' 2023)
    // The answer is the concatenation of the first letters of each bolded word:
    // affine plane, radically integral local field,
    // open oriented line section, jacobian,
    // orthogonal kernel embedding
    // => a p r i l f o o l s j o k e => aprilfoolsjoke

    cout << "aprilfoolsjoke" << endl;
    return 0;
}